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Answers (1)
y = x^2+x dy/dx = 2x+1 dy/dx= m m = 2x+1 At(2,3) m = 2(2)+1 m = 5 slope of normal line -1/5 Point (2,3) equation y-y1 = m (x-x1) y-3 = 5(x-2) : y-3 = -1/5(x-2) y-3 = 5x-10 : y-3 = -x/5+2/5 y = 5x-7 : y = -x/5+17/5 Equation of Tangent line y = 5x-7 Equation
