Mont

three variable are missing a+b+c=0, a²+b²+c²=3, and a⁴+b⁴+c⁴=? And a^5+b^5+c^5=10

1/(√7-1)-1/(√7-3)=a+b√c [√7-3-(√7-1)]/(10-4√7)=a+b√c (1-3)/(10-4√7)=a+b√c -2/2(5-2√7)=a+b√c -1/(5-2√7)=a+b√c -(5+2√7)/(25-28)=a+b√c -(5+2√7)/-3=a+b√c 5/3+2/3√7=a+b√c a=5/3 b=⅔ c=√7/3 Is this correct