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1/(√7-1)-1/(√7-3)=a+b√c[√7-3-(√7-1)]/(10-4√7)=a+b√c (1-3)/(10-4√7)=a+b√c -2/2(5-2√7)=a+b√c
1. 1 answer
2. 278 views
three variable are missing a+b+c=0, a²+b²+c²=3, and a⁴+b⁴+c⁴=? And a^5+b^5+c^5=10
1. 8 answers
2. 612 views