Ask a New Question
Search
Questions and answers by
Mirie
Questions (2)
Prove: [1/sqrt(2)] [sqrt(a) + sqrt(b)] <= sqrt(a + b) <= sqrt(a) + sqrt(b) for all non-negative real numbers a and b.
1 answer
696 views
Let a be a real number and let m, n be natural numbers such that m < n. Prove that if 0 < a < 1 --> a^n < a^m < 1.
So, what I
1 answer
627 views
