Answers by visitors named: Mima

I did it in moles but still the homework assignment website is not accepting these answers. My work: Initial PH = 9.24. moles of NH3= 0.01 moles of NH4= 0.01 After addition of HCl: moles of HCl added= 0.0006 moles of NH3 left= 0.0094 moles of NH4= 0.0106 PH= 9.19 Addition of NaOH: moles of Naoh= 0.0006 moles of NH4= 0.0094 moles of NH3= 0.0106 PH= 9.30 used HH equation in all, considering PKa of NH3= 9.25

Still wrong answer.

I got initial PH= 9.24 PH after HCl addition= 9.19 PH after NaOH addition= 9.3 so delta PH after HCl= 0.05 delta PH after NaOH= - 0.06 all these still wrong answers. could it be that I'm calculating the total volume wrong? should be 0.01+0.006 L?

You are right, thank you so so much. With addition of HCl, the Ph= -0.052. With addition of NAOH, the PH= 0.052. Thank you for all your efforts.

Thank you so much for replying, but I can't understand how to solve for partial pressure of CO2, when I get the [H^+] from PH then how to solve for partial pressure of CO2?

Thanks a lot, I got it.

Thanks, you mean finding n for acid or base? The graph represent only PH and volume we added for acid or base in ml.

Thank you for your reply.

Spectrophotometer. 2 ml of NH3 is added to Cu(NO3)2 to give it dark blue color. If we accidantely put 3 ml of NH3, would the absorbance reading by spec should be considered? Explain. I wrote we shouldn't consider the reading because it will give darker color than it should be and the reading would be beyond the expected range. Is that right?

Thank you so much.

I thought about that, but didn't know the initial and remaining N. Why initial N is 100?

The hint they gave us now is that this is a first intigrated order reaction, I do not get it, what the order of the reaction has to do with nuclear chemistry and decay?

Thanks, I got it right.

I'm getting 8.355E-22 Kg on for reactants, and 8.322E-22 Kg for products. I multiplied each mass they gave us in amu by 1.661E-27 to get it in Kg.

E= 0.438? I got the same answer (1.987) when I used the numbers you mentioned. Is the E standard potential = -0.26 -(-0.76)? Am I doing that right?(its cathode-Anode) right?

Got it, you are right, it's 0.439. Thank you so much, I was doing an easy math mistake (substracting before multiplying). Thanks again.

The answer is 285.4285714286

Im trusting you soup.

OMG SHE LIED BROOO I GOT LITERALLY 4/15.