Mets

This page lists questions and answers that were posted by visitors named Mets.

Questions

The following questions were asked by visitors named Mets.

Answers

The following answers were posted by visitors named Mets.

a=[F*(R+r)]/[(l/R)+m*R)] a=[22*(0.25+0.1875]/(0.0625/0.25)+2*(0.25) a=12.8333 This was correct. one of the few I got right. Part b is wrong. Need help on question 2 (torque) I am confused about the top view. I thought I understood it but I guess I don't.
11 years ago
Hi enjoy, I got the acceleration correct, but the x component of the friction force incorrect in part b. Question no. 2 on torque is confusing from the top view CW or CCW. Thanks.
11 years ago
Hi enjoy. I tried F=force - m*a = 22-(2*12.8333) = -3.6666 in the negative x direction. I am down to my last chance. Like with all the problems. Thanks, I am trying to keep my head above water. I still have a long way to go. I also had trouble with Questi...
11 years ago
Hi, Enjoy. I responded but I do not know what happened. f=force - (m*a) , 22-(2)*(12.83 3)= -3.666. x-componet in negative x direction. I am up to my last chance as on most problems. I need help on question no.1. Thanks.
11 years ago
ellie, Thanks. I thought this is the most difficult question. I had trouble with these type of problems throughout the course. I do not have any suggestions. at this point.
11 years ago
For question 5 ballistic missile m1= 5*10^24kg; r1=6000km; m2<<m1; alpha=30 degrees; r2=(5/2)r1=15000; G=6.674*10^-11. What is the initial speed of the projectile? My solution: Vo^2=g*range/sin(theta) Vo^2=6.674*10^-11*(r1+r2/sin30degrees) Vo^2=(6.674*10^...
11 years ago
Hi Geoff, Thanks for the tip. I would have entered it as entered my answer as -3.666. I entered as positive 3.666 and it was correct. Good call.
11 years ago
Hi Elena, The equation I used for to solve for Va is sqrt((5/4)*(G*m_1/r_1). It came out wrong. Is this the correct equation. Thanks.
11 years ago