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Mehari
Answers (2)
A. 4 are defective and 8 are non-defective P(2 are defective) = C(4,2)/C(12, 2) = 1/11 B. One lamp is defective means the other one is non- defective P(1- defective) = (8, 1)(4, 1)/(12, 2)= 16/33 C. P( at most onedefective)= P(no defective) + P(1-
A. 4 are defective and 8 are non-defective P(2 are defective) = C(4,2)/C(12, 2) = 1/11
