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Meenaakshi
Questions (18)
A saline solution is 20% salt.
How many gallons of water must be added to dilute the mixture to 8 gals of a 15% saline solution?
2 answers
1,465 views
Oil used to absorb benzene from gas is to be stripped with steam at P = 1atm to recover the benzene.Equlibrium at the operating
0 answers
481 views
Hi Dr.Bob,
Which is the correct formula for dinitrobis(ethylenediamine)cobalt(III) nitrate? I'm not sure which is the correct one
1 answer
719 views
When 6200g of ethylene glycol and 16600g terephtalic acid reacted completely to generate poly(ethyleneterephtalate)(PET),how
1 answer
502 views
Arrange these acids in terms of increasing acidity:
CH3COOH, NH3+CH2COOH, CH3CONHCH2COOH Dr.Bob asked me what NH3+CH2COOH
2 answers
596 views
Dr.Bob,
Arrange these acids in terms of increasing acidity: CH3COOH, NH3+CH2COOH, CH3CONHCH2COOH According to my Chem
3 answers
594 views
Arrange these acids in terms of increasing acidity:
CH3COOH, NH3+CH2COOH, CH3CONHCH2COOH My answer is
2 answers
526 views
Disulfide bonds in protein:
a) results from an oxidation of thiol b)help to maintain the shape of proteins c)can be broken by
0 answers
364 views
How many stereoisomers are possible for threonine?
0 answers
468 views
How many stereoisomers are there for 1,2-dichlorocyclopentane?
The answer options are 1,2,3 & 4. I think it is 4 because there is
3 answers
2,108 views
For a system where:
NH2OH + CH3NH3+ --> CH3NH2 + NH3OH+ 95% 95% 5% 5% State of equilibrium in the system is described by the
2 answers
3,335 views
500.0 mL of 0.220 mol/L HCl(aq) was added to a high quality insulated calorimeter containing 500.0mL of 0.200 mol/L
1 answer
3,699 views
500.0mL of 0.220 mol/L HCl(aq) was added to a high quality insulated calorimeter containing 500.0mL of 0.200mol/L NaOH(aq).Both
3 answers
1,457 views
When solving Hess law problems,do we need to use all the equations given to get the Htotal or just choose the relevant equations
1 answer
662 views
Given acidity constant,Ka of benzoic acid is 6.28 X 10^-5. pH of 0.15 molar solution of this acid is ?
Here is my method: Benzoic
1 answer
3,699 views
So,my second method is correct isn't it? The answer is -78.4kJ?
1 answer
288 views
But in the answer options:
a) -27.4 kJ b) -72.8 kJ c) -78.4 kJ d) -84.6kJ I attempted this problem in the other way.When using
1 answer
508 views
When pure sulfuric acid is dissolved in water,heat is evolved.To a calorimeter containing 300g of water at 20degree C,10.65g of
3 answers
1,896 views
Answers (10)
Hi Teresa, Always remember: ln x = loge(log base e)x log x = log10(log base 10)x Example : ln x = 2 loge x = 2 x = e^2 log x = 5 log10 x =5 x = 10^5 (Hope this two examples have given you a rough understanding) ln(x-4) = -3 ln(x-4) = loge(x-4),right?
Hi sasha, Let me explain the methods step by step : a)3x^2 ln(2x) For this question, product rule must be applied : uv = udv/dx + vdu/dx where u = 3x^2 & v = ln(2x) Differentiate u, du/dx = 6x(I'm sure you know the basic differentiation) Differentiate v
Hi Christopher, Let me explain the method of solving this problem: Given the area of the ring = 2123 ft^2 The formula for area is pi*r^2, where r is the radius Therefore,we need to find the r based on the area given 2123 ft^2 = pi*r^2 (work this out using
Thank you Dr.Bob & sorry for the inconvenience caused to you
Ok,that NH3+CH2COOH is obtained when 1 mol of glycine is added with a strong acid,which results in both amino & carboxyl groups to be fully protonated.
But Dr.Bob,from what I refer,NH3+CH2COOH is the strongest acid since it has both acid and NH3 protonated.Acetic acid is a weak acid,I'm not sure about the CH3CONHCH2COOH. That's what confuses me
Ok thank you Dr.Bob
Sorry what I meant was dividing the total heat with mole of NaOH ,not mass.
Ok,then how do I find the dH of NaOH? Do I need to use the total heat of the system and divide it by the mass of NaOH to get its dH ? I'm still confused Thank you
But in the answer options: a) -27.4 kJ b) -72.8 kJ c) -78.4 kJ d) -84.6kJ I attempted this problem in the other way.When using the q =mcdT,I added the mass of both water and sulfuric acid. q = (300g +10.65g)(4.184J/g.K)(6.55C) = 8513.43 J Then, I
