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Md Kafiul

Answers (1)

Distance covered along the pathway, s = sqrt(0.9^2 + 1.6^2) = 1.836 m Now, s = ut + ½*gt^2 => 1.836 = 0.5 * 9.8 * t^2 [since u=0] => t = 0.612 sec (Fall time)

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