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haha, on second thought, the 29 should be the denominator of t, as in my first post. It modifies the half-life of the radioactive material. Sorry!
DrBob222, yes, you're right. The problem should read as is, A(t)=(1/29)(1/2)^t with t in years. I got carried away!
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First, if you mean A(t)=A0(1/2)^(t/29) the parentheses are mandatory because of the PEMDAS rule. After 20 years, t=20 so A(20)=(1/2)^(20/29) pull out your calculator and find the correct answer. Do not forget the parentheses this time. Post your answer for
18-15=3 13+4=17 6-4=2 Yes, your answer is correct.
Can you check your expression, please. I am not sure if there is a typo in the second term.
A. Ethanol "dissolves" in water. In fact, it is miscible, i.e. can be mixed with water in any proportion. This property is often interpreted as "infinitely soluble". B. Iodine is only slightly soluble in water (1:3450).
Step 1:Write the chemical equation of the oxidation: CH4+2O2=CO2+2H2O This means that 1 mole of CH4 or 2 moles of O2 will give 1 mole of CO2 Step 2: find limiting reagent CH4: 6/(12+4*1)=6/16=0.4375 mol O2: 5/(2*16)=5/32=0.15625 mol Compare with the
Experimental probability is what we infer from an experiment. For example: if we toss a fair coin 100 times, head comes out 44 times. We say that head came out 44 times out of 100 (in this trial), and the experimental probability of head,
There are many steps in writing a program. You need to specify in which area you need help with, pseudocode, debugging, logic, or whatever. We are not going to post a turn-key program for you because you will not have learned anything. Learning to
The intuitive solution is by ratio assuming the population can be extrapolated by the sample, thus population =(600*(800/10)=48000.
Let x1=number of 1-point shots x2=number of 2-point shots x3=number of 3point shots "Josh scored 39 points in a game" => 3x3+2x2+x1=39.........(1) "the same number of 2-point shots as [3-point and free throws combined]" x2=x3+x1 .............(2) "scored
The best way to clear up your question is to post the assignment question, and tell us your interpretation or your doubts.
The thickness of the lens is not given, so assume it is a thin lens. Using the thin-lens approximation of the lens-maker's formula, P=1/f=(n-1)(1/R1-1/R2) where n=refractive index of lens material in air R1, R2 are radii of curvature of lens surfaces,
Since we are given the hypotenuse and one leg, we can find the other leg using Pythagoras theorem. The area is then the product of the two legs divided by two. Height (of the other leg) =√(3.7²-1.2²)=3.5 Base (given)=1.2 m So you have all information
At the beginning, there are 22*760=16720 food days. After 2 days, there are 20*760=15200 food days left. If this should last only 19 days, it will feed 15200/19=80 persons. You can therefore figure out how many more people came (in addition to the original
