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Mathhelper help

This page lists questions and answers that were posted by visitors named Mathhelper help.

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The following questions were asked by visitors named Mathhelper help.

The path of an object projected at a 45-degree angle with an initial velocity of 60 feet per second is given by the function h(x) = -32/((60)^2)x^2 + x, where x is the horizontal distance traveled in feet and h(x) is the object's height in feet. Use a gra...
4 years ago

Answers

The following answers were posted by visitors named Mathhelper help.

I got 136.9 feet Tell me how I did
4 years ago
Yes sir I did
4 years ago
On second try I got y= 3x^2 -6x + 7 Does that look good?
4 years ago
I got -7/3 How would I express it as an inequality?
4 years ago
My math was wrong I got it now 23.1 feet I think that's correct
4 years ago
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