Manam Ramu

This page lists questions and answers that were posted by visitors named Manam Ramu.

Questions

The following questions were asked by visitors named Manam Ramu.

Answers

The following answers were posted by visitors named Manam Ramu.

Given daily demand d=40 quarts per day std dev =6 quarts Ce= 35 cents Service level =Cs/(Cs+Ce) Optimal orders = mean demand + z * std dev 49 = 40 + z*6 => z=0.6666 from standard normal diistribution table service level will be 0.748 => Cs=104 cents.
5 years ago