Macin

Michaela is solving rational equations. A. What is the solution set of the equation ... x^2-7x+12 (all over or divided by) x^2+x-12 both equal to 3. What I did first was factor both equations geting (x-4) on the top and (x+4) on the bottom both equal to 3...

The only solution of the equation ... x&2+bx-18 over (divided by) -2x+4 equals 4.... When x=-17. I plugged in the number and replaced x with -17 and it looks like this... (-17)^2 +(-17x)-18 over 38. I just got lost.

x^2+2x-15 (all over) x-3 equals 3. (x-3) * x^2+2x-15 (all over) x-3 equals 3 *(x-3) x^2+2x-15=3x-9 x^2-x-6=0 (x-3)(x+2)=0 x-3=0 or x+2=0 x={3, -2} I did something wrong here but I'm not sure what I did that is wrong. What is my error? Or is it the solutio...