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MILY
Questions (6)
the fundamental theorem of calculus,
f(x)=∫(0,x) t^3+2t^2+ 2 dt, and find f"(x). my answer was: f'(x)=x^3+x^2 f"(x)=3x^2+2x it
2 answers
1,050 views
Evaluate the indefinite integral
(a.)∫√(cotx)csc^2xdx (b.)∫sec^3xtanxdx
1 answer
623 views
anti-derivation
given f"(x)=3x+0 and f'(-1)=1 and f(-1)=5 find f'(x)=? and find f(2)
1 answer
355 views
antiderivative.
find f. f'(x)= 3x^(-2), f(1)=f(-1)=0
1 answer
427 views
antiderivative.
find f. f'(x)= 3x^(-2), f(1)=f(-1)=0
0 answers
354 views
HARDER PARTS WAS 3(x^2+y^2)^2=26(y^2+y^2)
Find the equation of the tangent line to the curve (a lemniscate)
2 answers
617 views
Answers (3)
yea it is ∫ (t^3 + 2t^2 + 2) dt from 0 to x. thanks for ur help
oops my bad.. 26(x^2-y^2)
ok i got result for m. but i don't know where is b.. i forget how do y=mx+b