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Lowery
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125.0g each of two solids, lead (II) nitrate and pottassiuk iodide are dissolved in the same beaker. A reaction occurs that
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Mols of Pb(No3) 2 = .377? Mols of kl = .753?
1 Pb(NO3) and 2 mols of Kl?
Using the coefficients, convert mols KI to mols of PbI2. Do the same and convert mols Pb(NO)3 to mols KI. It is likely that the two values for mols PbI2 will not agree; the correct value in LR problems is ALWAYS the smaller value and the reagent