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Kshitija
Answers (2)
★ CONTINUE ★ = 5/13 (ii) Sec A = hypo / adj = AC/ AB = 13/12
Let , 13 cos A = 12 Cos A = adjacent/ hypo = 12/13 AB = 12 , AC = 13 By using Pythagoras theorem AC² = AB² + BC² (13)² = (12)² + BC² 169 = 144 + BC² 169 - 144 = BC² 25 = BC² BC = 5 (i) Sin A = opposite / hypo = BC/AC
