Kshitija
This page lists questions and answers that were posted by visitors named Kshitija.
Questions
The following questions were asked by visitors named Kshitija.
Answers
The following answers were posted by visitors named Kshitija.
Let , 13 cos A = 12 Cos A = adjacent/ hypo = 12/13 AB = 12 , AC = 13 By using Pythagoras theorem AC² = AB² + BC² (13)² = (12)² + BC² 169 = 144 + BC² 169 - 144 = BC² 25 = BC² BC = 5 (i) Sin A = opposite / hypo = BC/AC
4 years ago
★ CONTINUE ★ = 5/13 (ii) Sec A = hypo / adj = AC/ AB = 13/12
4 years ago