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Questions and answers by
Kritik Pachauri
Answers (1)
Let a is the side of the equilateral triangle. Then, Area of Δ =(√3/4)*a^2 s = (a+a+a)/2 = 3*a/2 Now, Inradius (r) = Area of Δ/s = (√3/4*a^2)/(3*a/2) = a/(2*√3) Circumradius(R) = (a*b*c)/4*(Area of Δ) = a^3/(√3/a^2) = a/√3 Exradii (r1) = (Area
