Kriss

Find all values of a, B so that the function f(x)=1 if x>3, f(x)=ax-10 if x<3, and f(x)=B otherwise is continuous everywhere. I think a is continuous everywhere since ax-10 is a polynomial, and b is continuous at x=3.

A garden is to be designed in the shape of a circular sector, with radius r and central angle theta. the garden is to have a fixed area A. for what value of R and theta will the length of the fencing be minimized?

Can someone give me a hand? Here's what i have so far: Use the intermediate value theorem to determine if the function: f(x)=x^3+3x^2-9x-10 has a zero in the interval [-1, 0] so this is what i have: f(-1)=-1^3+3(-1^2)-9(-1)-10=-1-3-9-10= -23 and f(0)=0^3+...