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Kramer
Questions (2)
Given a curve, say y^3 = x^2, and a value, say 4.
How can I find a point in which the curve will have slope 4?
2 answers
403 views
sin(5x)/sin(4x) = ?
How do I cancel them out to get a constant?
4 answers
351 views
Answers (2)
I understand the equation for slope in this case would be: dy/dx = 2x/3y. But how can you find a point that satisfies both 2x/3y and y^3 = x^2?
what property is this? in terms of a and b?
