Answers by visitors named: Khad

Best Answer - Chosen by Asker You are going to need graph paper, a protractor and a measuring ruler. Draw an x-y Cartesian coordinate , x-y axis. Problem starts at origin, (0,0). Call this point O From the origin measure off a line 60 degrees from the y-axis. The y-axis is North, (0 degrees) and your constructed line is the heading of the airplane. Using a suitable scale (I suggest 1 cm = 100 miles), measure off a distance of 5.8 cm along your constructed line. At the 5'8 cm mark, call this point A (for airplane) Return to the origin. Measure off 45 degrees from north (the y-axis) and draw another line. This is N 45 degrees W, and is really just the line that represents the wind coming from the southwest, southwest being 45 degrees to the west of south. Measure off 0.6 cm along this line from the origin. Label that point W (for wind). We now construct a parallelogram. At point P, draw OW', parallel to original OW and the same length. At point W, draw OP', parallel to original OP and the same length Call the point of intersection of OW' and OP' point T (for true heading) Draw the diagonal from O to T OT is the "vector" that gives the true direction and speed of the airplane. Measure with your protractor the angle from the y-axis (it will be about 50 degrees, called N 50 degrees E) and the length in cm. of the diagonal OT. Multiply the measured cm. by 100 to get its speed