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Kayrie
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Use the rotational energy equation, E = 0.5Iω², where I is the moment of inertia for a long thin rod with an axis through it's midpoint (I = (1/12)mL²). E = 0.5Iω² E = 0.5 [1/12)mL²] ω² E = (1/24) mL² ω² Find ω by multiplying the rpm by 2π and