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Karoline
Questions (2)
Differentiate using the product rule.
How do i get from dy/dx = d(uv)/dx = u dv/dx + v du/dx
1 answer
453 views
Differentiate y=(5x-2)^3(3-x)^6 using the product rule.
i don't get the step where they find the common factor could you help me
6 answers
1,124 views
Answers (3)
hey sorry, one more thing. How do you find -3 as in now I see the following common factors -3 how ?
ah OK, now i get it. Thank you so much!!
thanks! there is an example here and where i get lost is a step where it goes from dy/dx = d(uv)/dx = u dv/dx + v du/dx = (5x-2)^3[-6(3-x)^5]+(3-x)^6[15(5x-2)^2] = (5x-2)^2(3-x)^5(-30x+12+45-15x) is there a step between there that you could show me how to