Jurgi

Very important! It would be very appreciated if someone could help. There are four modules connected in series. Knowing that when the bypass diode in a module is activated the forward voltage drop on the diode is 0.4[V] , answer the following questions: A...

To find the answer is pretty simple. E= h*c/λ*q Where, h is the planck's constant c is the speed light in vacuum λ is the wavelength q is the elementary charge

Did you manage to find the right answer mate?

Did you manage to get the right answer?