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Juan Manuek
Questions (3)
How can I solve the following exercise: Use perturbation theory to calculate the energy levels of a particle in a box with a
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How can I solve the following ecercise: Use perturbation theory to calculate the energy levels of a particle in a box with a
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How can I solve the following ecercise: Use perturbation theory to calculate the energy levels of a particle in a box with a
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Answers (3)
H'(x=0) = 2V0 H'(X = a/2) = 0 H'(x= a) = 2 V (y is and) in spanish and I don't know wath does mean k+1 and k-1. It refers to l=1?
How can I solve the following ecercise: Use perturbation theory to calculate the energy levels of a particle in a box with a cosine function bottom. Let the box extend from x=a to x=a and let the perturbing potential be H' = V0[1+cos(2*Pi*m*x/a)]. This
bottom 2V0 or 2V is the potential in x=0