Joseph Zimba

This page lists questions and answers that were posted by visitors named Joseph Zimba.

Questions

The following questions were asked by visitors named Joseph Zimba.

Answers

The following answers were posted by visitors named Joseph Zimba.

Work done = ∆P.E W=(mhg)f - (mgh)i (mgh)i =0, since it was lying down And, h = ½(h of the marble) h= ½(3.4)=1.7m W= 180 kg × 9.8 m/s² × 1.7m W= 2,998.8 J W = 3.0 kJ