Answers by visitors named: Joseph

Thank you so much Ms. Sue. I could have not done this without you!

It did not put my answers in.

This was my guess for #2: p q ~(p AND q) ~(p AND q)Vp T T F FVT= T T F T TVT= T F T T TVF= T F F T TVF= T

Sorry.... the tables not supposed to turn out liek that. Can anyone show me how the table can be improved? Table 1: 4 vertical columns, 4 horizontal columns (on top) Table 2: 4 vertical columns, 4 horizontal columns (on top) Table 3: 3 vertical columns, 3 horizontal columns (on top) Would it be possible if I scanned the table and sent it through as a jpg image?

Purpose: The purpose of this lab exercise is to construct a table of relative strengths of oxidizing and reducing agents. By completing this exercise, you will see how more extensive tables of relative strengths of oxidizing and reducing agents have been developed. Procedure: Using the results from the three tables below, prepare a single table of relative strengths of oxidizing and reducing agents Table 1. Reactions of metals and nonmetals with solution of ions I2(aq) Cu2+(aq) Ag+(aq) Br2(aq) I-(aq) X X T T Cu(s) T X T T Ag(s) X X X T Br-(aq) X X X X Table 2.Reaction of metals and solutions of ions Ag+(aq) Pb2+(aq) Cu2+(aq) Zn2+(aq) Ag(s)X X X X Pb(s)T X T X Cu(s)T X X X Zn(s)T T T X Table 3. Reactions of nonmetals with solutions of ions Br-(aq) Cl-(aq) I-(aq) Br2(aq) X X T Cl2(aq) T X T I2(aq) X X X Legend: T = evidence redox reaction occured X = no evidence of redox reaction

*Please note For table 1 I2(aq), Cu2+(aq), Ag+(aq) and Br2(aq) are supposed to be shifted to the right since they are horizontal. I-(aq), Cu(s), Ag(s) and Br-(aq) are vertical. For table 2 Ag+(aq), Pb2+(aq), Cu2+(aq) and Zn2+(aq) are supposed to be shifted to the right since they are horizontal. Ag(s), Pb(s), Cu(s) and Zn(s) are vertical. For table 3 Br-(aq), Cl-(aq) and I-(aq) are supposed to be shifted to the right since they are horizontal. Br2(aq), Cl2(aq) and I2(aq) are vertical.

No problem, I will write it as you say:)

Purpose: The purpose of this lab excersise is to construct a table of relative strengths of oxidizing and reducing agents. By completing this excersise, you will see how extensive tables of relative strengths of oxidizing and reducing agents have been developed. Procedure: Using the results from the three tables below, please prepare a single table of relative strengths of oxidizing and reducing agents. Reactions of metals and non metals with solution of ions Reaction 1: I2(aq)Cu^+2(aq) Ag^+(aq)Br2(aq) Column 1---Column 2---Column 3---Column 4---Column 5 I-(aq)---X---X---T---T Cu(s)---T---X---T---T Ag(s)---X---X---X---T Br-(aq)---X---X---X---X Reaction of metals and solution of ions Reaction 2: Ag+(aq)Pb2+(aq)Cu2+(aq)Zn2+(aq) Column 1---Column 2---Column 3---Column 4---Column 5 Ag(s)---X---X---X---X Pb(s)---T---X---T---X Cu(s)---T---X---X---X Zn(s)---T---T---T---X Reactions of nonmetals with solutions of ions Column 1---Column 2---Column 3---Column 4 Br2(aq)---X---X---T Cl2(aq)---T---X---T I2(aq)---X---X---X Legend: T = evidence redox reaction occured X = no evidence of redox reaction

*Forgot to add, reaciton 3 is Br-(aq) Cl-(aq) I-(aq)

When I finish with the other two reactions, would you mind reviewing my work?

I found a pattern and I was wondering if it applies to all reactions. The more times there is evidence of a redox reaction occuring for an element, the higher this element will be on the list?

Of the reactions that occurred spontaneously in the individual tables, what types of qualitative changes would you observe that would indicate the reaction is proceeding?

ONe more question DrBob :) For the reactions that occurred spontaneously in the individual tables, balance these reactions assuming they are in an acidic solution. Thanks for any further assistance we appreciate it

Reaction 1 I 2(aq) Cu2 + (aq) Ag + (aq) Br2 (aq) Reaction 2 Ag + (aq) Pb2 + (aq) Cu2 + (aq) Zn2 +(aq) Reaction 3 Br - (aq) Cl - (aq) I - (aq)

please help me with this problem? I have the answer but I need to know how to do it. Use the point on the line and the slope of the line to find three additional points through which the line passes point slope ((7,-2) m= 1/2

i still don't get how to do it

thanks now i get it

Thanks

Do you want to poop or fart???

I tried the / but that didn't worked either =[

Thanks. But I'm still getting it wrong, cause maybe the sig figs are off by a little. What did you get for this problem?

I solved it and got 42.94 torr, so by 2 sig figs i rounded it up to 43 torr. What did you get?

nevermind i had it right the whole time. thank you

nevermind. i got it. thank you dr. bob for showing me how to do it tho

Haha yeah thanks i already figured it out. thank you tho

use a calculator!

plug in the x values in the equation to find the y values.

No, this is all of the information that is provided.

This is the question that was provided, no more information.

What is the Journal Entry for: Sold goods to Smithsons for $700 that costs $300. Terms of n/30 were offered. As a courtesy to Smithsons, $125 of frieght was added to the invoice for which cash was paid directly to the UPS by Opals, INC? Need This answer ASAP!

job seeking and courage

IDK... my BFF Jill?

i have the same problem and im stuck too

this is due tomorrow

The plane is flying at an altitude of 8 miles and is 175 miles from the runway, as measured from the ground. What angle will the plane's path make with the runway? Round your answer to the nearest hundredth.

I don't get which one is Tfinal, and Tinitial for both of them can you explain it? thank you

The equation require 2 pressure but there is only 1 in this problem

Could I use STP( 760 torr and 273K) to plug in the equation ?

ok, i got them. just want to make sure the answer are correct. thanks

thanks, i typed it wrong

Is it O2(S) is denser right? Because it's solid

decomposition of H2O2 to water and O2

Do you mean a la uno voy a la clase ciencias? If so, it means "at one o'clock I go to science class."

sin 38 = .6157 .6157 = 150/x 150/.6157 = 243.6

Thank you

1) C=3 ;H=2 and Cl=1 so the empirical formula of the compound is C3H2Cl. I seem not to get the others clear.

C=3 ;H=2 and Cl=1. Therefore the empirical formula of the compound is C3H2Cl The others don't seem clear to me

CH=78g/mol but the relative atomic mass of C=12 and H=1 therefore the molecular mass would be (12+1)n=78 g/mol 13n = 78 g/mol n=6 the molecular formula is C6H6 .

You are given pH which is (-log[H^+] ). so first you take 10^-2 to get the Molarity of [H^+], then you convert 500 mL to Liters so divide 500 by 1000. Finally you take Molarity times volume in liters to get moles of H^+. 10^-2 = .01 500/1000 = .5 .01 * .5 = 5*10^-3 = Moles of H^+ ions.

Ms Sue pls i'm writing for the motion

And if you were asked to write a principals report for class?

I did not understand your responce, could you please clarify?

Thank you for all the research!!

Here is my answer so far. Do you know of anything else I can add to it?? The steps that must be taken prior to writing and effective persuasive essay is to build an outline of ideas and thoughts, elaborate those thoughts and ideas, do some research on the topic, define your attitude regarding the matter of the essay and finally study your prospective audience. There are many people who have a difficult time planning a persuasive essay, but by following these steps it will help with the process. You should design your essay by figuring out the order in which you will be presenting your evidence. All the arguments in a persuasive essay should be backed up by reliable evidence. You should take time to brainstorm and write down all of your thoughts about the topic.

Do you know of anything I have left out?

I just wrote this paper so I do not think it needs any changes. I was wanting someone to proof read it.

WHATEVER!!!!!

Thank you Reiny for your help.

The cirucumference of a ballon is 75 inches and the diameter is 12 inches what is the volume?

D) would actually be approximately 9.23 seconds. 1362/16=85.125

The answer is 0

I believe the period time will be tripled from the original time at 2.55s because the distance that the spring was puled down was 3 times the original length. Answer= 2.55 seconds

What is the correct answer?

I have Kc= [(0.065)(0.130)^2]/(0.190^2) Kc= 0.030429 This answer was incorrect. Can you please help correct me?

250

a) find the partial derivatives of each, and just plug in 1 for x and 3 for y (values should be close to 0)/ b) in using the difference quotients, take the limit as h approaches infinity of both each derivative, plugging in 0.1 for x and y in each one. It's better that you think critically about how the definition of the derivatives applies not only in 2D, but in 3-space as well. You'll gain a better intuition.

8; 2,622 g

Solution My mean is 175.5 My standard deviation is=90.57 Sample=25 So the probability is Formula to be used: P(X>190)=P((X-mean)/s sqrt of my sample is = 5 (190-175.5) / 90.57/5) 14.5 / 18.114 calculator says 0.8004858120790548746825659710721 I check the z-table and I see -.8 under the z of 0.00 correlates to .2119 =0.2119

Awesome, thanks!

Given the info provided, this is a simple Q=mc(delta)T question. Simply plug and chug. m=10kg c=specific heat = 900j/kgxC (delta)T= 5 C The answer should be 4.5x10^4 J

Tinny insects such as mosquitoes can seat on the surface of water.which physical principle makes this possible ?

4^-1.5

Are you sure this is a solid b+

i got maximum to be -¼ and minimum to be -1 and i got it wrong

my answer is also B

thank you I hope it is correct

a)E(R1+R2)/R2

yes

i meant manometer

570J is the correct answer

The question is poorly worded. But that is the way I got the answer.

For number 3 the adjective is three sided and wooden? 4)simple and unusual? 5)unlimited? 6) much and first?

On number one is some an adjective because it's describing sense? Thank you

Top carnivore in a food chain

Can you show me the formula

Thank you Ms Sue. You were a big help

Thanks. It was 12.5

@Peter What about the non-conservative work lost with the tension force?

8,390

Thank you

d = 31 Thank you Ms. Sue

Thanks everyone i Got a 100% also!!! :) REAL ANSWERS ARE 1)c 2)a 3)c 4)a 5)a 6)c 7)d 8)d 9)a 10)c 11)a 12)a 13)c 14)c 15)d 16)d 17)c

a.) Having decay constant as t=0.693/decay constant. Therefore decay constant=0.693/t (i.e time). Decay constant=0.693/30 =0.02

VALVE

Would it be two? Since HHT and HTH? or HHT, THH, Hth? Thanks

B. smog

Mean=Sum of observations/total no: of observations here 50 is the mean therefore sum of the observation=50*100 so the sum will be 5000 when the value is changed from 100 to 110....only 10 is increased... therefore sum of observations will be increased by ten.... 5000+10(note:100-110)=5010 Mean=Number of Observations/total number of observations So the mean=5010/100=50.1 i have a small doubt in this problem.....anybody please say my answer is correct or not....if it is wrong please suggest the right way

Use the equation Q = mc∆T Q =(m)(c)(∆T) =(22.0g)(4.184J/g°C)(75°C) =6903.6J =6900J (if you need to round to nearest sig fig) Hope this helps!

Quick Answer: "I" Explanation: Since you're forming an iconic bond, you want to get the total valance electrons to 8. Elements under 1A all have 1 valance electron, so all you really need to do is find an element with 7 electrons which under VIIIA column(7th column). The only elements in that 7th column are F, Cl, Br, I, and At. Therefore, I is the correct answer in this situation. Hopefully this helps you out! I tried my best to explain how I got the answer.

how many hours are in a day? 12! So... just take the 6 as the numerator and the 12 as the denominator (6/12) and if you simplify so it will be (1/2) and if you turn that into s percentage it will be %50. THE ANSWER IS AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAaa