John Paul Espano

This page lists questions and answers that were posted by visitors named John Paul Espano.

Questions

The following questions were asked by visitors named John Paul Espano.

Answers

The following answers were posted by visitors named John Paul Espano.

Although this problem is practically incorrect. In theory, the water vapor behaves as a perfect gas; therefore, we apply: PV = mRT Work Done (approx.), W = Pdv = P(mRT/P) = mRT= 1kg-mol x 8.3145 KJ/Kg-mol-K x(100+273) = 3101.3085 KJ Answer: Approx. 3101.3...