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John Paul Espano
Answers (1)
Although this problem is practically incorrect. In theory, the water vapor behaves as a perfect gas; therefore, we apply: PV = mRT Work Done (approx.), W = Pdv = P(mRT/P) = mRT= 1kg-mol x 8.3145 KJ/Kg-mol-K x(100+273) = 3101.3085 KJ Answer: Approx. 3101.31
