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John Eris
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Question: Calculate the solubility (g/L) of CuBr at 25 degrees celsius in 0.0110 M CoBr2. Ksp of CuBr = 5.3*10^-9.
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Thank so much Dr. Bob!!
Sorry: for solubility in water x multiplied by the molar mass equals 1.5 g/L
Follow up work: CuBr --> Cu + Br CoBr2 --> Co + 2 Br Set up for solubility in pure water: 5.3*10^-9 = x^2 x= 1.5 g/L Set up (?) for solubility in 0.011 M CoBr2: 5.3*10^-9 = (x)(0.022+x)
