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Jensor
Answers (1)
(i) I'm still working on this (ii) n=100 => [n(n-3)]/2 = [100(100-3)]/2 = 4850 (iii) [n(n-3)]/2 =170 => n2-3n-340=0 n = 20 and n=-17. But sides couldn't be negative => n=20 (sides) b) Call the total number of diagonals of n+1 sides polygon is x =>
