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Jeena
Questions (9)
A metal rod is made of 26kg of iron, how much heat must be supplied to the radiator to raise its temperature from 25 Celsius to
7 answers
583 views
During a road test,a driver brakes a 1420kg car moving at 64.8km/h [W]. The car slows down and comes to a stop after moving 729m
4 answers
3,451 views
Citric acid (pKa1 = 3.13, pKa2 = 4.76, pKa3 = 6.40) is found in citrus fruit. Calculate the approximate pH of lemon juice, which
3 answers
1,293 views
SO2(g) + NO2(g) reverse reaction arrow SO3(g) + NO (g)
At a given temperature, analysis of an equilibrium mixture found [SO2] =
4 answers
1,268 views
SO2(g) + NO2(g) reverse reaction arrow SO3(g) + NO (g)
At a given temperature, analysis of an equilibrium mixture found [SO2] =
5 answers
859 views
3H2(g) + N2(g) reverse reaction arrow 2NH3(g)
What factors would affect the equilibrium constant for the reaction above? (Select
3 answers
1,995 views
In the reaction 2 H2(g) + S2(g) reverse reaction arrow 2 H2S(g), Kc = 6.28 multiplied by 103 at 900 K. What is the equilibrium
3 answers
554 views
Do you mind posting up an example for that please? It would help out a out: What is the activation energy for a reaction whose
3 answers
470 views
What is the activation energy for a reaction whose rate is tripled by a temperature increase from 28 to 53 C? I understand that
7 answers
642 views
Answers (12)
Okay thank you sir
Youre right sir. Am i going to use this eqn Q=mc deltaT Where my change in temp will be 79.5-55 C?
The first and second question are related sir. But i cant see the use of the initial temp on the second question. To solve for the mass on the 2nd question what change in temp will i use?
So I found that you would have to set it up using (4.1)(3.1)/(2.9)(x-1.1). The x includes the .5 of NO2 already added, so to find how much was added to the original, find x and just subtract .5. The "x" value was the new initial value used to raise SO3 to
i thought you would have to decrease x from SO2?
The answer is only temperature changes. The equilibrium constant becomes larger with a temperature change, the forward reaction is favored and the eq. shifts to the right. If the constant becomes smaller, the reverse reaction is favored and shifts to the
I tried to answer the hwk using this tip for part B, but I didn't get it right...is there another way to set it up?
for this one, when we set up the ice chart, and we have the M of HI, and we have to subtract x, would we subtract 2x because the mols of HI is two?
I also just found this site. DrBob222 is great!
actually, the right answer was 35.8 KJ
I got 896.3 KJ. Does this seem right?
but I don't have the K or the Ea. Do you mind posting a sample?
