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Jared Jackson
Answers (2)
thats for if your student number is prime
a ) v(t) = at^2 + bt + c, 1st 0a + 0b +c = 10000 3rd 9a + 3b + c = 7975 6th 36a + 6b + c = 6400 9th 81a+9b+c = 5275 b) 9a + 3b + c = 7975 B = (7975-10,000-9a)/(3) 81a+9b+c = 5275 81a+9((7975-10,000-9a)/(3))+10000 = 5275 a= 25 9a + 3b + c = 7975 9(25) + 3b