JandBsDad

7^(11)*7^(1/13) is the way it's written. You don't subtract the powers in this expression. To subtract powers the expression would have to look like, 7^(11)/7^(13)=7^(11-13)=7^(-2). Hope this helps

matix solution |1 1 1 | [x y z]'= [14 0 18]' |4 0 1 | |1 0 2 | H*[x y z]' = [14 0 18]' (' stands for transpose; in this case makes row vector a column vector) Answer inv(H)*H*[x y z]'= inv(H)*[14 0 18]' [x y z] = inv(H)*[14 0 18]' inverting a 3x3 matrix i...

x=days 135kg +3.5kg/day*x =weight SalePrice= $(1.65-0.01*x)/kg*weight cost= $0.8/day*x profit=Saleprice-cost profit(x)=(1.65-0.01x)(135 +3.5x)-0.8x profit(x)= 1.65*135+1.65*3.5x-0.01*135x-0.01*3.5x^2-0.8x = 222.750+4.4250x-0.035x^2-0.8x = 222.750+3.625x-0...