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Janavi
Questions (7)
A current of 3.40 A is passed through a Ni(NO3)2 solution for 1.80 hours. How much nickel is plated out of the solution?
3 answers
1,109 views
Calculate the pH of the resulting solution if 25.0 mL of 0.250 M HCl(aq) is added to
(a) 35.0 mL of 0.250 M NaOH(aq). (b) 15.0 mL
3 answers
2,709 views
Calculate the change in pH when 5.00 mL of 0.100 M HCl(aq) is added to 100.0 mL of a buffer solution that is 0.100 M in NH3(aq)
1 answer
914 views
Consider the following reaction.
A(aq) (Two way arrows) 2B(aq) Kc = 7.94*10^-6 at 500K If a 2.70 M sample of A is heated to 500K
2 answers
5,184 views
At a certain temperature, the Kp for the decomposition of H2S is 0.813.
H2S (Two wa arrow) H2(g) + S(g) Initially, only H2S is
2 answers
3,686 views
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction
2NO(g) +
2 answers
5,314 views
When the oxide of generic metal M is heated at 25.0 °C, only a negligible amount of M is produced.
O2M(s) ----> M(s) +O2(g)
10 answers
1,209 views
Answers (13)
I found the answer to a however i keep doing something wrong for b
Some one please help
Wait so, you are getting 0.65 from the total mL but shouldnt this be 65/1000 or 0.065?
Thanks Karan!!
Thank you sooo much Karan!
1: Set all the delta g's for solids equal to 0 2:Find thr delta g for the gases. 3:Find the delta g for the second equation. 4:Add the delta g's for the 2 questions together. 5: Solve for the value of Q using the equation -Delta G not =RTLnQ
Thank you Karan!
I can learn by example, this is an example please, work it out so I can do the rest. This question does not even count towards my final grade but the others like it do, so please help me.
I did not calculate it for rxn 1 please please give me a step by step run down I honestly do not know how to do this problem and I have several more like it I really need a template to work off of to do the others please help me.
347
Some one please help I really do not understand this question one bit.
How do I calculae the K for Reaction 2?
Delta G = G not + RTlnQ ==69.0 +(0.008314*298K*(ln((0.8^2)/((0.25^2)*0.15)) =-69.0 +10.46383111 =-58.53616889
