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JRose
Questions (2)
Given f(x)=4x^2+2x-9, what is f'(a)?
A. f'(a)=6a+2 B. f'(a)=6a-9 C. f'(a)=8a+2 D. f'(a)=4a+2-9
3 answers
377 views
Given the function y=x^2-4, write the parametric equations that would allow the same path for x=t-3.
A. x=t-3, y=t^2-6t-13 B.
1 answer
356 views
Answers (2)
Use the equations x(t)=v(cos theta t)+x1 and y(t)=v(sin theta t)+y1. First x(t): (1.5cos87°t)+0= x(t)=0.079t+0 Second y(t): (1.5sin87°t)+0= y(t)=1.5t+0 Since it's 7 seconds, plug 7 into t: x(t)=0.079(7)+0 which is 0.5 y(t)=1.5(7)+0 which is 10.5 Hence,
It's C?