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JQuiroz
Answers (2)
1-B 2-A 3-D 4-C 5-D 6-D 7-A 8-B 9-C 10-B 11-C 12-D 13-B 14-C 15-B 16-D 17-C 18-could be D 19-A 20-B
sinxsin5x sinucosv= 1/2[cos(u-v)-cos(u+v)] = 1/2[cos(x-5x)-cos(x+5x)] = 1/2[cos(-4x)-cos(6x)] = 1/2cos4x-1/2cos6x
