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(i) Convert the masses of reactants to moles. 356 g of CO is 356/28 = 12.7 moles. 65 g of H2 is 65/2.016 = 32.2 moles. There are MORE than twice as many moles of H2, compared to CO, so CO is the limiting reactant. (ii) The number of moles of CH3OH that can
Step by step explanation Bottom=X Right= 4x+10 Left= 3+x Final Answer 6x+13
