Ask a New Question

Questions and answers by

Ibrahim R

Answers (2)

2.02g
Answer Requested The amount that precipitates should be the difference between the mass of KCl present initially and the solubility value for KCl at 0 ∘C: mass precipitate=(initial dissolved mass)−(solubility at 60∘C)=42g−27g=15gKCl precipitates

Ask a New Question

Archives
Contact Us
Newest
Privacy Policy
Terms of Use
© 2025