I'm correct and not a prick liar

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The following questions were asked by visitors named I'm correct and not a prick liar.

Answers

The following answers were posted by visitors named I'm correct and not a prick liar.

Consider the following reaction: 2Ag+(aq) + Cu(s) ↔ Cu2+(aq) + 2Ag(s) Step 1: Write the two half-reactions. Ag+(aq) + e- ↔ Ag(s) Cu(s) ↔ Cu2+(aq) + 2e- Step 2: Determine the cathode and anode. Anode: Cu(s) ↔ Cu2+(aq) + 2e- Cathode: Ag+(aq) + e- ↔ Ag(s)

Step 3: Construct the Diagram. Cu(s) | Cu2+(aq) || Ag+(aq) | Ag(s)