Hquiambao
This page lists questions and answers that were posted by visitors named Hquiambao.
Questions
The following questions were asked by visitors named Hquiambao.
Answers
The following answers were posted by visitors named Hquiambao.
r of A = r of B θ of A = 11° θ of B = 17.4° v of A = 15.3 m/s v of B = ? tan(θA) = (vA^2)/(rg) derive to: r = (vA^2)/(tan(θA))(g) r=(15.3^2)/(tan11)(9.8) r=122.8866 m tan(θB) = (vB^2)/(rg) derive to: vB=sqrt[(r)(tanθB)(g)] vB=sqrt[(122.8866)(tan17.4)(9.8)...
7 years ago
r of A = r of B θ of A = 11° θ of B = 17.4° v of A = 15.3 m/s v of B = ? tan(θA) = (vA^2)/(rg) derive to: r = (vA^2)/(tan(θA))(g) r=(15.3^2)/(tan11)(9.8) r=122.8866 m tan(θB) = (vB^2)/(rg) derive to: vB=sqrt[(r)(tanθB)(g)] vB=sqrt[(122.8866)(tan17.4)(9.8)...
7 years ago