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Hquiambao
Answers (2)
r of A = r of B θ of A = 11° θ of B = 17.4° v of A = 15.3 m/s v of B = ? tan(θA) = (vA^2)/(rg) derive to: r = (vA^2)/(tan(θA))(g) r=(15.3^2)/(tan11)(9.8) r=122.8866 m tan(θB) = (vB^2)/(rg) derive to: vB=sqrt[(r)(tanθB)(g)]
r of A = r of B θ of A = 11° θ of B = 17.4° v of A = 15.3 m/s v of B = ? tan(θA) = (vA^2)/(rg) derive to: r = (vA^2)/(tan(θA))(g) r=(15.3^2)/(tan11)(9.8) r=122.8866 m tan(θB) = (vB^2)/(rg) derive to: vB=sqrt[(r)(tanθB)(g)]
