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In Figure 8-34, a 1.2 kg block is held at rest against a spring with a force constant k = 695 N/m. Initially, the spring is
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Figure 8-33 shows a 1.50 kg block at rest on a ramp of height h. When the block is released, it slides without friction to the
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Answers (1)
energy in f riction= mg*mu*.05m = 5.886 leftover energy= 1/2 m 1.5^2 = 1.35 So, If I add the leftover energy and the energy in friction I get the initial energy. Then what??