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Questions and answers by
Henry Wosor
Answers (1)
2K(s) + 1/2O2(g)---->K2O deltaH=−363.17 kJ or better still, K2O --->2K(s) + 1/2O2(g)deltaH=363.17 take note that the equation is reversed above. 2K(s)---->2K(g) deltaH=2(+89.24 kJ/mol )=178.48kJ 2K(g)---->2K+(g) deltaH=2(+419 kJ/mol )=838kJ
