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Hasini
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If the graphs of $f$ and $g$ intersect at $(x,y)$, then $y = f(x)=g(x)$, so \[x^3+x^2+x-1=x^3-x^2+x+1.\]Moving all the terms to the left-hand side gives $2x^2-2=0$, so $x=\pm1$. Substituting into $g$ we find the points of intersection to be \[