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Haimbondi

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first calcu the no. of mole of KOH c=n/v n=c.v =0.22*(10.0/1000) =0.0022 moles Final conc.= 0.0022/(250/1000)= 0.0088M pOH= -log[OH]= -log[0.0088M]=2.06 PH=14-2.06= 11.94

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