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Questions (2)
how do not understand how to do this
Log X + Lob (X-3) = 1 I know I do this Log X(X-3)=1 then I do this Log X^(2) - 3X = 1 then I
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I'm doing a lab and all i need to know is how to derive an equation
I'm accelrating over 5m on a flat surface and people timed
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Answers (3)
ok um so Log (X^(2) - 3X) = 1 x^2 - 3x = 10^1 what allows you to put in the value ten and get ride of the log on the other side? What if the value wasn't one would u just do 10^X? x^2 - 3x - 10 = 0 (x-5)(x+2) = 0 x = 5 or x = -2
ok um so Log (X^(2) - 3X) = 1 x^2 - 3x = 10^1 what allows you to put in the value ten and get ride of the log on the other side? What if the value wasn't one would u just do 10^X? x^2 - 3x - 10 = 0 (x-5)(x+2) = 0 x = 5 or x = -2
what exactly is antilog?
