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Gourab g
Answers (1)
Normal reaction from 40 kg slab on 10 kg block = 10 * 9.81 = 98.1 N Static frictional force = 98.1 * 0.6 N is less than 100 N applied => 10 kg blck will slide on 40 kg slab and net force on it = 100 N - kinetic friction = 100 - 98.1 * 0.4 = 61 N => 10 kg
