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GloryRose
Answers (1)
Let X be the length of material of rod A and 30-X be the length of material of rod B. We have 0.065 = (0.045/30)*X + [30-X]*(0.075/30) = 0.0015*X + 0.075 - 0.0025*X or 0.001*X = 0.075 - 0.065 = 0.010 or X = 10 cm. So initial length of rod A was 10 cm and
