Gilraed

The E[Y] is equal to E[N]*E[X], being Y=X1+...+Xn. Now, we know that N is the number of coin flips, and Xk is independent and uniformly distributed between 0 and 3. This means that E[X]=3*1/2=3/2, with a variance of 3^2/12=3/4. Now, for N we are given 1/p...