Georges

Hi, can you help me please with this: translate the following sentence into equation: Two numbers have a sum of 20, which is the the product of one number and the square of the other is 50. Thanks

Find the following indefinite integral ∫ (x^2 -8)/ (x^2 -16) dx My work ∫ (x^2 - 8) * ∫ (1/(x^2 - 16) ∫ (x^2 - 8) = [(x^3)/(3) - 8x)] + C ∫ (1/(x^2 - 16) = ∫ [(-1/8)/(x+4)] + [(1/8)/(x-4)] = (-1/8)*ln|(x+4)| +(1/8)*|(x-4)| + C So I get this, ∫ (x^2 -8)/ (...

1 divided by 3 =0.33 2 1/3= (2*3)+1=6+1=7 then u have 7/3 7 divided by 3 = 2.33

C'est devant de vous/toi