Geee

Find the diameter of a pulley which is driven at 360 rpm by a belt moving at 40 ft/s. Then in 1 s the pulley turns through an angle theta measuring 12 pi radians and a point on the rim travels a distance s= 40 ft.

Thank you for the respond!! I appreciate it. But it says on my paper 360 rev/min = 360 (2pi/60) rad/s = 12pi rad/s and so D= 2r = 2(s/theta) = 2(40/12pi) ft = 20/3pi ft = 2.12 ft should be the answer :( I have 2 more if that's alright. A point on the rim...