Ask a New Question
Search
Questions and answers by
FurrierThanYou
Answers (2)
The arrangement around the table must be of the form BGBGBGBG. We can place the first boy anywhere; we then have $3! = 6$ ways of placing the remaining boys and $4! = 24$ ways of placing the girls. This gives a total of $6\cdot 24 = \boxed{144}$
Incorrect, It is 144
