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Franki
Questions (2)
a+7b=17, a+2b=2
1 answer
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Given this equation:
2P2O5 + 6H2O ---> 4H3PO4. If you begin with 4.8 grams of p2o5 and 15.2 grams h20, what will be your limiting
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Answers (3)
I think i figured it out... can you tell me if this is right. i did 4.8 g P2O5 * 1mol/142 *.03 mols P2O5/ 1g * 6H20 / 2P2O5*18.0G/1. Instead of getting 13.4, I got 13.58. Is that still right. If not can you please show me how you did it! Thanks again, I
Thanks for your help! :) I'm stuck... so i did 4.8 g P2O5 * 1mol/142. I got .03. then what do i do after that?
how do i know what the excess reagent is?
